What is the answer to |x^2+2x-36|=12 ?

The answer to |x^2+2x-36|=12 is x=-8\lor x=-6\lor x=4\lor x=6

Solve for x: |x^2+2x-36|=12

The solution is x=-8\lor x=-6\lor x=4\lor x=6

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x^{2} + 2 x - 36 = 12

x = - 8 or x = - 6 or x = 4 or x = 6

Solution steps

x^{2} + 2 x - 36 = 12

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

x^{2} + 2 x - 36 = - 12 or x^{2} + 2 x - 36 = 12

x^{2} + 2 x - 36 = - 12 or x^{2} + 2 x - 36 = 12

(x = - 6 or x = 4) or (x = - 8 or x = 6)

x = - 8 or x = - 6 or x = 4 or x = 6

\frac{2 m ^{- 4}}{( 2 m ^{- 4} ) ^{3}}

4 p + 4 \geq 12

a^{2} - 9 a + 20 = 0

3 r^{2} + 16 r + 5

- 3 y^{2} + 5 y - 6 = 0

What is the answer to |x^2+2x-36|=12 ?
The answer to |x^2+2x-36|=12 is x=-8\lor x=-6\lor x=4\lor x=6
Solve for x: |x^2+2x-36|=12
The solution is x=-8\lor x=-6\lor x=4\lor x=6