What are the solutions to the equation x^2+(x^2-7)=13 ?

The solutions to the equation x^2+(x^2-7)=13 are x=sqrt(10),x=-sqrt(10)

Find the zeros of x^2+(x^2-7)=13

The zeros of x^2+(x^2-7)=13 are x=sqrt(10),x=-sqrt(10)

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x^{2} + (x^{2} - 7) = 13

x = 10, x = - 10

Decimal Notation

x = 3.16227 \dots, x = - 3.16227 \dots

Solution steps

x^{2} + (x^{2} - 7) = 13

Remove parentheses:

(a) = a

x^{2} + x^{2} - 7 = 13

Add similar elements:

x^{2} + x^{2} = 2 x^{2}

2 x^{2} - 7 = 13

Move

7

to the right side

2 x^{2} = 20

Divide both sides by

2

x^{2} = 10

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 10, x = - 10

5 y^{2} = - 20 y

7 (a - 10) = 13 - 2 (2 a + 3)

\frac{z}{6} = 8

\frac{7 x ^{- 1} y ^{3}}{x ^{2} y ^{- 2}} \cdot \frac{( 3 x y ^{2} ) ^{- 1}}{x y}

2 x + 5 = 0

What are the solutions to the equation x^2+(x^2-7)=13 ?
The solutions to the equation x^2+(x^2-7)=13 are x=sqrt(10),x=-sqrt(10)
Find the zeros of x^2+(x^2-7)=13
The zeros of x^2+(x^2-7)=13 are x=sqrt(10),x=-sqrt(10)