What are the solutions to the equation 2x^2=3-x^2 ?

The solutions to the equation 2x^2=3-x^2 are x=1,x=-1

Find the zeros of 2x^2=3-x^2

The zeros of 2x^2=3-x^2 are x=1,x=-1

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2 x^{2} = 3 - x^{2}

x = 1, x = - 1

Solution steps

2 x^{2} = 3 - x^{2}

Move

x^{2}

to the left side

3 x^{2} = 3

Divide both sides by

3

x^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 1, x = - 1

1 = 1

- 1 = - 1

x = 1, x = - 1

3 x^{2} - 6 x - 4 = 0

x^{5} - 7 x^{4} + 9 x^{3} + 23 x^{2} - 50 x + 24

\frac{2 π}{3.6}

1690 \cdot ⎩ ⎨ ⎧ \frac{[ ( 1 + 0.07 ) ^{38} - 1 ]}{0.07} ⎭ ⎬ ⎫

(x + 1) (x + 2) = 0

What are the solutions to the equation 2x^2=3-x^2 ?
The solutions to the equation 2x^2=3-x^2 are x=1,x=-1
Find the zeros of 2x^2=3-x^2
The zeros of 2x^2=3-x^2 are x=1,x=-1