What are the solutions to the equation 36x^2-12x+1=4 ?

The solutions to the equation 36x^2-12x+1=4 are x= 1/2 ,x=-1/6

Find the zeros of 36x^2-12x+1=4

The zeros of 36x^2-12x+1=4 are x= 1/2 ,x=-1/6

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36 x^{2} - 12 x + 1 = 4

x = \frac{1}{2}, x = - \frac{1}{6}

Decimal Notation

x = 0.5, x = - 0.16666 \dots

Solution steps

36 x^{2} - 12 x + 1 = 4

Move

4

to the left side

36 x^{2} - 12 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 36 ( - 3 )}{2 \cdot 36}

(- 12)^{2} - 4 \cdot 36 (- 3) = 24

x_{1, 2} = \frac{- ( - 12 ) \pm 24}{2 \cdot 36}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 24}{2 \cdot 36}, x_{2} = \frac{- ( - 12 ) - 24}{2 \cdot 36}

x = \frac{- ( - 12 ) + 24}{2 \cdot 36} : \frac{1}{2}

x = \frac{- ( - 12 ) - 24}{2 \cdot 36} : - \frac{1}{6}

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - \frac{1}{6}

t^{2} + 8 t

x^{2} + 5 x - 20 = 0

1^{2} + b^{2} = 2^{2}

x - 3 = 2 + x

3 x^{2} - 16 x + 6 = 0

What are the solutions to the equation 36x^2-12x+1=4 ?
The solutions to the equation 36x^2-12x+1=4 are x= 1/2 ,x=-1/6
Find the zeros of 36x^2-12x+1=4
The zeros of 36x^2-12x+1=4 are x= 1/2 ,x=-1/6