What are the solutions to the equation 0=-x^2-2x+1 ?

The solutions to the equation 0=-x^2-2x+1 are x=-1-sqrt(2),x=sqrt(2)-1

Find the zeros of 0=-x^2-2x+1

The zeros of 0=-x^2-2x+1 are x=-1-sqrt(2),x=sqrt(2)-1

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0 = - x^{2} - 2 x + 1

x = - 1 - 2, x = 2 - 1

Decimal Notation

x = - 2.41421 \dots, x = 0.41421 \dots

Solution steps

0 = - x^{2} - 2 x + 1

Switch sides

- x^{2} - 2 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 ( - 1 ) \cdot 1}{2 ( - 1 )}

(- 2)^{2} - 4 (- 1) \cdot 1 = 22

x_{1, 2} = \frac{- ( - 2 ) \pm 2 2}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 2}{2 ( - 1 )}, x_{2} = \frac{- ( - 2 ) - 2 2}{2 ( - 1 )}

x = \frac{- ( - 2 ) + 2 2}{2 ( - 1 )} : - 1 - 2

x = \frac{- ( - 2 ) - 2 2}{2 ( - 1 )} : 2 - 1

The solutions to the quadratic equation are:

x = - 1 - 2, x = 2 - 1

45 a b^{2} - 15 a^{2} b c

3 t^{2} - 6 t - 11 = 0

0 = (x - 8)^{2}

∣ x - 3 ∣ \leq 2 x - 5

5 u^{4} - 40 u^{3} + 35 u^{2}

What are the solutions to the equation 0=-x^2-2x+1 ?
The solutions to the equation 0=-x^2-2x+1 are x=-1-sqrt(2),x=sqrt(2)-1
Find the zeros of 0=-x^2-2x+1
The zeros of 0=-x^2-2x+1 are x=-1-sqrt(2),x=sqrt(2)-1