What are the solutions to the equation 2t^2=72 ?

The solutions to the equation 2t^2=72 are t=6,t=-6

Find the zeros of 2t^2=72

The zeros of 2t^2=72 are t=6,t=-6

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2 t^{2} = 72

t = 6, t = - 6

Solution steps

2 t^{2} = 72

Divide both sides by

2

t^{2} = 36

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = 36, t = - 36

36 = 6

- 36 = - 6

t = 6, t = - 6

j^{2} - 24 j + 23

(a^{2} + 1)^{2} + 5 (a^{2} + 1) - 24

6 - 5 x \leq - 44

y^{2} - 6 y + 25 = 0

(8 a^{- 3})^{- \frac{2}{3}}

What are the solutions to the equation 2t^2=72 ?
The solutions to the equation 2t^2=72 are t=6,t=-6
Find the zeros of 2t^2=72
The zeros of 2t^2=72 are t=6,t=-6