What are the solutions to the equation 2(x-5)^2-9=0 ?

The solutions to the equation 2(x-5)^2-9=0 are x= 3/(sqrt(2))+5,x=-3/(sqrt(2))+5

Find the zeros of 2(x-5)^2-9=0

The zeros of 2(x-5)^2-9=0 are x= 3/(sqrt(2))+5,x=-3/(sqrt(2))+5

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2 (x - 5)^{2} - 9 = 0

x = \frac{3}{2} + 5, x = - \frac{3}{2} + 5

Decimal Notation

x = 7.12132 \dots, x = 2.87867 \dots

Solution steps

2 (x - 5)^{2} - 9 = 0

Move

9

to the right side

2 (x - 5)^{2} = 9

Divide both sides by

2

(x - 5)^{2} = \frac{9}{2}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 5 = \frac{9}{2} : x = \frac{3}{2} + 5

Solve

x - 5 = - \frac{9}{2} : x = - \frac{3}{2} + 5

The solutions to the quadratic equation are:

x = \frac{3}{2} + 5, x = - \frac{3}{2} + 5

x^{2} + 1

y, x^{2} = y^{2}

- 2 x^{2} + x = - 6

x^{2} + 2 x + 2

a x^{2} + b x + c

What are the solutions to the equation 2(x-5)^2-9=0 ?
The solutions to the equation 2(x-5)^2-9=0 are x= 3/(sqrt(2))+5,x=-3/(sqrt(2))+5
Find the zeros of 2(x-5)^2-9=0
The zeros of 2(x-5)^2-9=0 are x= 3/(sqrt(2))+5,x=-3/(sqrt(2))+5