What are the solutions to the equation roots x^2-2x+2 ?

The solutions to the equation roots x^2-2x+2 are x=1+i,x=1-i

Find the zeros of roots x^2-2x+2

The zeros of roots x^2-2x+2 are x=1+i,x=1-i

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roots

x^{2} - 2 x + 2

x = 1 + i, x = 1 - i

Solution steps

x^{2} - 2 x + 2

The roots are the intercepts with the x-axis

(y = 0)

x^{2} - 2 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 2 : 2 i

x_{1, 2} = \frac{- ( - 2 ) \pm 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 i}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 i}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 i}{2 \cdot 1} : 1 + i

x = \frac{- ( - 2 ) - 2 i}{2 \cdot 1} : 1 - i

The solutions to the quadratic equation are:

x = 1 + i, x = 1 - i

x^{2} + x + 1

x^{2} + 4

x^{2} + 4 x + 5

x, z = x^{2} + y^{2}

What are the solutions to the equation roots x^2-2x+2 ?
The solutions to the equation roots x^2-2x+2 are x=1+i,x=1-i
Find the zeros of roots x^2-2x+2
The zeros of roots x^2-2x+2 are x=1+i,x=1-i