What are the solutions to the equation roots x^2+8x+c ?

The solutions to the equation roots x^2+8x+c are x=-4+sqrt(-c+16),x=-sqrt(-c+16)-4

Find the zeros of roots x^2+8x+c

The zeros of roots x^2+8x+c are x=-4+sqrt(-c+16),x=-sqrt(-c+16)-4

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roots

x^{2} + 8 x + c

x = - 4 + - c + 16, x = - - c + 16 - 4

Solution steps

x^{2} + 8 x + c

The roots are the intercepts with the x-axis

(y = 0)

x^{2} + 8 x + c = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot c}{2 \cdot 1}

Simplify

8^{2} - 4 \cdot 1 \cdot c : 2 16 - c

x_{1, 2} = \frac{- 8 \pm 2 16 - c}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 2 16 - c}{2 \cdot 1}, x_{2} = \frac{- 8 - 2 16 - c}{2 \cdot 1}

x = \frac{- 8 + 2 16 - c}{2 \cdot 1} : - 4 + - c + 16

x = \frac{- 8 - 2 16 - c}{2 \cdot 1} : - - c + 16 - 4

The solutions to the quadratic equation are:

x = - 4 + - c + 16, x = - - c + 16 - 4

x, x^{2} + y^{2} = r (x)^{2}

s^{2} + 2 s + 2

3 d^{2} - 9 d + 3 = 0

x^{2} + 9

x^{2} + b x + c

What are the solutions to the equation roots x^2+8x+c ?
The solutions to the equation roots x^2+8x+c are x=-4+sqrt(-c+16),x=-sqrt(-c+16)-4
Find the zeros of roots x^2+8x+c
The zeros of roots x^2+8x+c are x=-4+sqrt(-c+16),x=-sqrt(-c+16)-4