What are the solutions to the equation roots s^2+2s+2 ?

The solutions to the equation roots s^2+2s+2 are s=-1+i,s=-1-i

Find the zeros of roots s^2+2s+2

The zeros of roots s^2+2s+2 are s=-1+i,s=-1-i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

roots

s^{2} + 2 s + 2

s = - 1 + i, s = - 1 - i

Solution steps

s^{2} + 2 s + 2

The roots are the intercepts with the x-axis

(y = 0)

s^{2} + 2 s + 2 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 2 : 2 i

s_{1, 2} = \frac{- 2 \pm 2 i}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 2 + 2 i}{2 \cdot 1}, s_{2} = \frac{- 2 - 2 i}{2 \cdot 1}

s = \frac{- 2 + 2 i}{2 \cdot 1} : - 1 + i

s = \frac{- 2 - 2 i}{2 \cdot 1} : - 1 - i

The solutions to the quadratic equation are:

s = - 1 + i, s = - 1 - i

3 d^{2} - 9 d + 3 = 0

x^{2} + 9

x^{2} + b x + c

x^{2} + 2 x + 4

x, x^{2} + y^{2} + z^{2} - 4 x + 12 y - 14 z + 40 = 0

What are the solutions to the equation roots s^2+2s+2 ?
The solutions to the equation roots s^2+2s+2 are s=-1+i,s=-1-i
Find the zeros of roots s^2+2s+2
The zeros of roots s^2+2s+2 are s=-1+i,s=-1-i