What are the solutions to the equation x(x-3)=-6+3(x-1) ?

The solutions to the equation x(x-3)=-6+3(x-1) are x=3

Find the zeros of x(x-3)=-6+3(x-1)

The zeros of x(x-3)=-6+3(x-1) are x=3

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x (x - 3) = - 6 + 3 (x - 1)

x = 3

Solution steps

x (x - 3) = - 6 + 3 (x - 1)

Expand

x (x - 3) : x^{2} - 3 x

Expand

- 6 + 3 (x - 1) : 3 x - 9

x^{2} - 3 x = 3 x - 9

Move

9

to the left side

x^{2} - 3 x + 9 = 3 x

Move

3 x

to the left side

x^{2} - 6 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 9 = 0

x_{1, 2} = \frac{- ( - 6 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 6 )}{2 \cdot 1}

\frac{- ( - 6 )}{2 \cdot 1} = 3

x = 3

The solution to the quadratic equation is:

x = 3

x^{2} - 24 x + 140 = 0

A, A = π r^{2}

y, x^{2} y^{2} = x^{2} + y^{2}

x^{2} + 4 x + 8

x^{2} + 6 x + 10 = - x

What are the solutions to the equation x(x-3)=-6+3(x-1) ?
The solutions to the equation x(x-3)=-6+3(x-1) are x=3
Find the zeros of x(x-3)=-6+3(x-1)
The zeros of x(x-3)=-6+3(x-1) are x=3