What are the solutions to the equation 14+3x^2=26 ?

The solutions to the equation 14+3x^2=26 are x=2,x=-2

Find the zeros of 14+3x^2=26

The zeros of 14+3x^2=26 are x=2,x=-2

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14 + 3 x^{2} = 26

x = 2, x = - 2

Solution steps

14 + 3 x^{2} = 26

Move

14

to the right side

3 x^{2} = 12

Divide both sides by

3

x^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 4, x = - 4

4 = 2

- 4 = - 2

x = 2, x = - 2

x, 3 x^{2} + 12 x = 0

x^{2}

6 x^{2} + 8 x + 9

x, f = a (x - h)^{2} + k

s^{2} + 2 s + 5

What are the solutions to the equation 14+3x^2=26 ?
The solutions to the equation 14+3x^2=26 are x=2,x=-2
Find the zeros of 14+3x^2=26
The zeros of 14+3x^2=26 are x=2,x=-2