What are the solutions to the equation roots x^2+x-1 ?

The solutions to the equation roots x^2+x-1 are x=(-1+sqrt(5))/2 ,x=(-1-sqrt(5))/2

Find the zeros of roots x^2+x-1

The zeros of roots x^2+x-1 are x=(-1+sqrt(5))/2 ,x=(-1-sqrt(5))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

roots

x^{2} + x - 1

x = \frac{- 1 + 5}{2}, x = \frac{- 1 - 5}{2}

Solution steps

x^{2} + x - 1

The roots are the intercepts with the x-axis

(y = 0)

x^{2} + x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 1) = 5

x_{1, 2} = \frac{- 1 \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 5}{2 \cdot 1}, x_{2} = \frac{- 1 - 5}{2 \cdot 1}

x = \frac{- 1 + 5}{2 \cdot 1} : \frac{- 1 + 5}{2}

x = \frac{- 1 - 5}{2 \cdot 1} : \frac{- 1 - 5}{2}

The solutions to the quadratic equation are:

x = \frac{- 1 + 5}{2}, x = \frac{- 1 - 5}{2}

- x^{2} - 4 x - 2

(x + 4)^{2} - 38 = - 22

x^{2} + 9 = 3

y, x^{2} - 2 x y + y^{2} = 0

3 p^{2} + 11 p = 4

What are the solutions to the equation roots x^2+x-1 ?
The solutions to the equation roots x^2+x-1 are x=(-1+sqrt(5))/2 ,x=(-1-sqrt(5))/2
Find the zeros of roots x^2+x-1
The zeros of roots x^2+x-1 are x=(-1+sqrt(5))/2 ,x=(-1-sqrt(5))/2