What are the solutions to the equation roots x^2-4x+4 ?

The solutions to the equation roots x^2-4x+4 are x=2

Find the zeros of roots x^2-4x+4

The zeros of roots x^2-4x+4 are x=2

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roots

x^{2} - 4 x + 4

x = 2

Solution steps

x^{2} - 4 x + 4

The roots are the intercepts with the x-axis

(y = 0)

x^{2} - 4 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 4 = 0

x_{1, 2} = \frac{- ( - 4 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 4 )}{2 \cdot 1}

\frac{- ( - 4 )}{2 \cdot 1} = 2

x = 2

The solution to the quadratic equation is:

x = 2

a, a^{2} = b^{2}

2 x^{2} + 12 x = 18

4 (x + 7)^{2} + 22 = 38

x^{2} - 2 x - 2 = 6

14 - 3 x^{2} = 8

What are the solutions to the equation roots x^2-4x+4 ?
The solutions to the equation roots x^2-4x+4 are x=2
Find the zeros of roots x^2-4x+4
The zeros of roots x^2-4x+4 are x=2