What are the solutions to the equation completesquare 2x^2+12x=18 ?

The solutions to the equation completesquare 2x^2+12x=18 are x=3sqrt(2)-3,x=-3sqrt(2)-3

Find the zeros of completesquare 2x^2+12x=18

The zeros of completesquare 2x^2+12x=18 are x=3sqrt(2)-3,x=-3sqrt(2)-3

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2 x^{2} + 12 x = 18

x = 32 - 3, x = - 32 - 3

Decimal Notation

x = 1.24264 \dots, x = - 7.24264 \dots

Solution steps

2 x^{2} + 12 x = 18

Divide both sides by

2

\frac{2 x ^{2} + 12 x}{2} = \frac{18}{2}

x^{2} + 6 x = 9

Rewrite in the form

(x + a)^{2} = b

(x + 3)^{2} = 18

For

the solutions are

f (x) = a, - a

Solve

x + 3 = 18 : x = 32 - 3

Solve

x + 3 = - 18 : x = - 32 - 3

The solutions to the quadratic equation are:

x = 32 - 3, x = - 32 - 3

4 (x + 7)^{2} + 22 = 38

x^{2} - 2 x - 2 = 6

14 - 3 x^{2} = 8

4 (3 x - 8)^{2} = 27

s^{2} + s + 1

What are the solutions to the equation completesquare 2x^2+12x=18 ?
The solutions to the equation completesquare 2x^2+12x=18 are x=3sqrt(2)-3,x=-3sqrt(2)-3
Find the zeros of completesquare 2x^2+12x=18
The zeros of completesquare 2x^2+12x=18 are x=3sqrt(2)-3,x=-3sqrt(2)-3