What are the solutions to the equation roots x^2-2x-3 ?

The solutions to the equation roots x^2-2x-3 are x=3,x=-1

Find the zeros of roots x^2-2x-3

The zeros of roots x^2-2x-3 are x=3,x=-1

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roots

x^{2} - 2 x - 3

x = 3, x = - 1

Solution steps

x^{2} - 2 x - 3

The roots are the intercepts with the x-axis

(y = 0)

x^{2} - 2 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 3) = 4

x_{1, 2} = \frac{- ( - 2 ) \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 4}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 4}{2 \cdot 1}

x = \frac{- ( - 2 ) + 4}{2 \cdot 1} : 3

x = \frac{- ( - 2 ) - 4}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 3, x = - 1

3 (x + 5)^{2} = 12

y, x^{2} + x y + y^{2} = 0

- b^{2} + 7 \cdot b - 10 = 0

x^{2} + 2 x + 2 = 0

x^{2} = \frac{5.6}{2.45}

What are the solutions to the equation roots x^2-2x-3 ?
The solutions to the equation roots x^2-2x-3 are x=3,x=-1
Find the zeros of roots x^2-2x-3
The zeros of roots x^2-2x-3 are x=3,x=-1