What are the solutions to the equation x^2+3x=-4x ?

The solutions to the equation x^2+3x=-4x are x=0,x=-7

Find the zeros of x^2+3x=-4x

The zeros of x^2+3x=-4x are x=0,x=-7

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x^{2} + 3 x = - 4 x

x = 0, x = - 7

Solution steps

x^{2} + 3 x = - 4 x

Move

4 x

to the left side

x^{2} + 7 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot 0 = 7

x_{1, 2} = \frac{- 7 \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 7}{2 \cdot 1}, x_{2} = \frac{- 7 - 7}{2 \cdot 1}

x = \frac{- 7 + 7}{2 \cdot 1} : 0

x = \frac{- 7 - 7}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

x = 0, x = - 7

x, x^{2} + x y + y^{3} = 1

3 (x + 4)^{2} = 39

x^{2} + 3 x - 23 = 5

2 (x + 3)^{2} - 27 = 19

14 + 3 x^{2} = 26

What are the solutions to the equation x^2+3x=-4x ?
The solutions to the equation x^2+3x=-4x are x=0,x=-7
Find the zeros of x^2+3x=-4x
The zeros of x^2+3x=-4x are x=0,x=-7