What are the solutions to the equation 3(x+4)^2=39 ?

The solutions to the equation 3(x+4)^2=39 are x=sqrt(13)-4,x=-sqrt(13)-4

Find the zeros of 3(x+4)^2=39

The zeros of 3(x+4)^2=39 are x=sqrt(13)-4,x=-sqrt(13)-4

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3 (x + 4)^{2} = 39

x = 13 - 4, x = - 13 - 4

Decimal Notation

x = - 0.39444 \dots, x = - 7.60555 \dots

Solution steps

3 (x + 4)^{2} = 39

Divide both sides by

3

(x + 4)^{2} = 13

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 4 = 13 : x = 13 - 4

Solve

x + 4 = - 13 : x = - 13 - 4

The solutions to the quadratic equation are:

x = 13 - 4, x = - 13 - 4

x^{2} + 3 x - 23 = 5

2 (x + 3)^{2} - 27 = 19

14 + 3 x^{2} = 26

x^{2} - 10 x + 16

2 x^{2} - 16 x = 12 x - 48

What are the solutions to the equation 3(x+4)^2=39 ?
The solutions to the equation 3(x+4)^2=39 are x=sqrt(13)-4,x=-sqrt(13)-4
Find the zeros of 3(x+4)^2=39
The zeros of 3(x+4)^2=39 are x=sqrt(13)-4,x=-sqrt(13)-4