What are the solutions to the equation 14+3x^2=26 ?

The solutions to the equation 14+3x^2=26 are x=2,x=-2

Find the zeros of 14+3x^2=26

The zeros of 14+3x^2=26 are x=2,x=-2

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14 + 3 x^{2} = 26

x = 2, x = - 2

Solution steps

14 + 3 x^{2} = 26

Move

14

to the right side

3 x^{2} = 12

Divide both sides by

3

x^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 4, x = - 4

4 = 2

- 4 = - 2

x = 2, x = - 2

x^{2} - 10 x + 16

2 x^{2} - 16 x = 12 x - 48

18 - x^{2} = 13

x^{2} - x - 2

x^{2} - 16 = 0

What are the solutions to the equation 14+3x^2=26 ?
The solutions to the equation 14+3x^2=26 are x=2,x=-2
Find the zeros of 14+3x^2=26
The zeros of 14+3x^2=26 are x=2,x=-2