What are the solutions to the equation roots x^2-10x+16 ?

The solutions to the equation roots x^2-10x+16 are x=8,x=2

Find the zeros of roots x^2-10x+16

The zeros of roots x^2-10x+16 are x=8,x=2

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roots

x^{2} - 10 x + 16

x = 8, x = 2

Solution steps

x^{2} - 10 x + 16

The roots are the intercepts with the x-axis

(y = 0)

x^{2} - 10 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 16 = 6

x_{1, 2} = \frac{- ( - 10 ) \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 6}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 6}{2 \cdot 1}

x = \frac{- ( - 10 ) + 6}{2 \cdot 1} : 8

x = \frac{- ( - 10 ) - 6}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

x = 8, x = 2

2 x^{2} - 16 x = 12 x - 48

18 - x^{2} = 13

x^{2} - x - 2

x^{2} - 16 = 0

x^{2} + x + 2

What are the solutions to the equation roots x^2-10x+16 ?
The solutions to the equation roots x^2-10x+16 are x=8,x=2
Find the zeros of roots x^2-10x+16
The zeros of roots x^2-10x+16 are x=8,x=2