What are the solutions to the equation 5x^2+7x+9=5-3x ?

The solutions to the equation 5x^2+7x+9=5-3x are x=(-5+sqrt(5))/5 ,x=-(sqrt(5)+1)/(sqrt(5))

Find the zeros of 5x^2+7x+9=5-3x

The zeros of 5x^2+7x+9=5-3x are x=(-5+sqrt(5))/5 ,x=-(sqrt(5)+1)/(sqrt(5))

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5 x^{2} + 7 x + 9 = 5 - 3 x

x = \frac{- 5 + 5}{5}, x = - \frac{5 + 1}{5}

Decimal Notation

x = - 0.5527864045, x = - 1.44721 \dots

Solution steps

5 x^{2} + 7 x + 9 = 5 - 3 x

Move

3 x

to the left side

5 x^{2} + 10 x + 9 = 5

Move

5

to the left side

5 x^{2} + 10 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 5 \cdot 4}{2 \cdot 5}

1 0^{2} - 4 \cdot 5 \cdot 4 = 25

x_{1, 2} = \frac{- 10 \pm 2 5}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 10 + 2 5}{2 \cdot 5}, x_{2} = \frac{- 10 - 2 5}{2 \cdot 5}

x = \frac{- 10 + 2 5}{2 \cdot 5} : \frac{- 5 + 5}{5}

x = \frac{- 10 - 2 5}{2 \cdot 5} : - \frac{5 + 1}{5}

The solutions to the quadratic equation are:

x = \frac{- 5 + 5}{5}, x = - \frac{5 + 1}{5}

x^{2} + 6 x + 13

(4 x - 5) (- x + 2) = 0

(5 x + 7)^{2} - (- 2 x + 5)^{2} = 0

x^{2} + 20 x + c

y, 4 x^{2} - 16 x + 4 y^{2} + 16 = 0

What are the solutions to the equation 5x^2+7x+9=5-3x ?
The solutions to the equation 5x^2+7x+9=5-3x are x=(-5+sqrt(5))/5 ,x=-(sqrt(5)+1)/(sqrt(5))
Find the zeros of 5x^2+7x+9=5-3x
The zeros of 5x^2+7x+9=5-3x are x=(-5+sqrt(5))/5 ,x=-(sqrt(5)+1)/(sqrt(5))