What are the solutions to the equation (19x-3)(9+x)=0 ?

The solutions to the equation (19x-3)(9+x)=0 are x= 3/19 ,x=-9

Find the zeros of (19x-3)(9+x)=0

The zeros of (19x-3)(9+x)=0 are x= 3/19 ,x=-9

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(19 x - 3) (9 + x) = 0

x = \frac{3}{19}, x = - 9

Decimal Notation

x = 0.15789 \dots, x = - 9

Solution steps

(19 x - 3) (9 + x) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

19 x - 3 = 0 or 9 + x = 0

Solve

19 x - 3 = 0 : x = \frac{3}{19}

Solve

9 + x = 0 : x = - 9

The solutions to the quadratic equation are:

x = \frac{3}{19}, x = - 9

5 x^{2} + 33 = 3

- x^{2} - 8 x + 12 = 0

81 x^{2} + 36 x + 4 = 0

3 x^{2} + 23 x + 15

4 - 3600 \cdot + x^{2} = 0

What are the solutions to the equation (19x-3)(9+x)=0 ?
The solutions to the equation (19x-3)(9+x)=0 are x= 3/19 ,x=-9
Find the zeros of (19x-3)(9+x)=0
The zeros of (19x-3)(9+x)=0 are x= 3/19 ,x=-9