What are the solutions to the equation roots 3x^2-x-5 ?

The solutions to the equation roots 3x^2-x-5 are x=(1+sqrt(61))/6 ,x=(1-sqrt(61))/6

Find the zeros of roots 3x^2-x-5

The zeros of roots 3x^2-x-5 are x=(1+sqrt(61))/6 ,x=(1-sqrt(61))/6

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roots

3 x^{2} - x - 5

x = \frac{1 + 61}{6}, x = \frac{1 - 61}{6}

Solution steps

3 x^{2} - x - 5

The roots are the intercepts with the x-axis

(y = 0)

3 x^{2} - x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 3 ( - 5 )}{2 \cdot 3}

(- 1)^{2} - 4 \cdot 3 (- 5) = 61

x_{1, 2} = \frac{- ( - 1 ) \pm 61}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 61}{2 \cdot 3}, x_{2} = \frac{- ( - 1 ) - 61}{2 \cdot 3}

x = \frac{- ( - 1 ) + 61}{2 \cdot 3} : \frac{1 + 61}{6}

x = \frac{- ( - 1 ) - 61}{2 \cdot 3} : \frac{1 - 61}{6}

The solutions to the quadratic equation are:

x = \frac{1 + 61}{6}, x = \frac{1 - 61}{6}

4 x^{2} + 37 = - 20 x

x^{2} + x + 4

3 x^{2} - 5 x^{2} = 0

6 x^{2} + x = 222

h^{2} = 10 h - 3^{2}

What are the solutions to the equation roots 3x^2-x-5 ?
The solutions to the equation roots 3x^2-x-5 are x=(1+sqrt(61))/6 ,x=(1-sqrt(61))/6
Find the zeros of roots 3x^2-x-5
The zeros of roots 3x^2-x-5 are x=(1+sqrt(61))/6 ,x=(1-sqrt(61))/6