What are the solutions to the equation 25(5-4x)^2-15=-14 ?

The solutions to the equation 25(5-4x)^2-15=-14 are x= 6/5 ,x= 13/10

Find the zeros of 25(5-4x)^2-15=-14

The zeros of 25(5-4x)^2-15=-14 are x= 6/5 ,x= 13/10

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25 (5 - 4 x)^{2} - 15 = - 14

x = \frac{6}{5}, x = \frac{13}{10}

Decimal Notation

x = 1.2, x = 1.3

Solution steps

25 (5 - 4 x)^{2} - 15 = - 14

Move

15

to the right side

25 (5 - 4 x)^{2} = 1

Divide both sides by

25

(5 - 4 x)^{2} = \frac{1}{25}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

5 - 4 x = \frac{1}{25} : x = \frac{6}{5}

Solve

5 - 4 x = - \frac{1}{25} : x = \frac{13}{10}

The solutions to the quadratic equation are:

x = \frac{6}{5}, x = \frac{13}{10}

y, x^{2} + 4 x y + y^{2} = 1

x^{2} + 53 = 14 x

27 x^{2} - 36 x - 37 = 0

8 t^{2} - 26 t + 15 = 0

4 x^{2} - 4 x = - 13

What are the solutions to the equation 25(5-4x)^2-15=-14 ?
The solutions to the equation 25(5-4x)^2-15=-14 are x= 6/5 ,x= 13/10
Find the zeros of 25(5-4x)^2-15=-14
The zeros of 25(5-4x)^2-15=-14 are x= 6/5 ,x= 13/10