What are the solutions to the equation 27x^2-36x-37=0 ?

The solutions to the equation 27x^2-36x-37=0 are x=(6+7sqrt(3))/9 ,x=(6-7sqrt(3))/9

Find the zeros of 27x^2-36x-37=0

The zeros of 27x^2-36x-37=0 are x=(6+7sqrt(3))/9 ,x=(6-7sqrt(3))/9

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27 x^{2} - 36 x - 37 = 0

x = \frac{6 + 7 3}{9}, x = \frac{6 - 7 3}{9}

Decimal Notation

x = 2.01381 \dots, x = - 0.68048 \dots

Solution steps

27 x^{2} - 36 x - 37 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 36 ) \pm ( - 36 ) ^{2} - 4 \cdot 27 ( - 37 )}{2 \cdot 27}

(- 36)^{2} - 4 \cdot 27 (- 37) = 423

x_{1, 2} = \frac{- ( - 36 ) \pm 42 3}{2 \cdot 27}

Separate the solutions

x_{1} = \frac{- ( - 36 ) + 42 3}{2 \cdot 27}, x_{2} = \frac{- ( - 36 ) - 42 3}{2 \cdot 27}

x = \frac{- ( - 36 ) + 42 3}{2 \cdot 27} : \frac{6 + 7 3}{9}

x = \frac{- ( - 36 ) - 42 3}{2 \cdot 27} : \frac{6 - 7 3}{9}

The solutions to the quadratic equation are:

x = \frac{6 + 7 3}{9}, x = \frac{6 - 7 3}{9}

8 t^{2} - 26 t + 15 = 0

4 x^{2} - 4 x = - 13

4 w^{2} + 20 w + 25 = 0

3 x^{2} - 2 x + 4 = 5

x^{2} - (2 x - 21)^{2} = 144

What are the solutions to the equation 27x^2-36x-37=0 ?
The solutions to the equation 27x^2-36x-37=0 are x=(6+7sqrt(3))/9 ,x=(6-7sqrt(3))/9
Find the zeros of 27x^2-36x-37=0
The zeros of 27x^2-36x-37=0 are x=(6+7sqrt(3))/9 ,x=(6-7sqrt(3))/9