What are the solutions to the equation -15x^2-3=2(7x^2-1.5) ?

The solutions to the equation -15x^2-3=2(7x^2-1.5) are x=0

Find the zeros of -15x^2-3=2(7x^2-1.5)

The zeros of -15x^2-3=2(7x^2-1.5) are x=0

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- 15 x^{2} - 3 = 2 (7 x^{2} - 1.5)

x = 0

Solution steps

- 15 x^{2} - 3 = 2 (7 x^{2} - 1.5)

Expand

2 (7 x^{2} - 1.5) : 14 x^{2} - 3

- 15 x^{2} - 3 = 14 x^{2} - 3

Move

3

to the right side

- 15 x^{2} = 14 x^{2}

Move

14 x^{2}

to the left side

- 29 x^{2} = 0

Divide both sides by

- 29

x = 0

y, x^{2} = 2 y^{2}

(x - 1)^{2} - 12 = 26

x^{2} - 4 x = 4 x

80 x^{2} = - 16

5 x^{2} - 40 x = - 60

What are the solutions to the equation -15x^2-3=2(7x^2-1.5) ?
The solutions to the equation -15x^2-3=2(7x^2-1.5) are x=0
Find the zeros of -15x^2-3=2(7x^2-1.5)
The zeros of -15x^2-3=2(7x^2-1.5) are x=0