What are the solutions to the equation 80x^2=-16 ?

The solutions to the equation 80x^2=-16 are x= 1/(sqrt(5))i,x=-1/(sqrt(5))i

Find the zeros of 80x^2=-16

The zeros of 80x^2=-16 are x= 1/(sqrt(5))i,x=-1/(sqrt(5))i

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80 x^{2} = - 16

x = \frac{1}{5} i, x = - \frac{1}{5} i

Solution steps

80 x^{2} = - 16

Divide both sides by

80

x^{2} = - \frac{1}{5}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{1}{5}, x = - - \frac{1}{5}

- \frac{1}{5} = \frac{1}{5} i

- - \frac{1}{5} = - \frac{1}{5} i

x = \frac{1}{5} i, x = - \frac{1}{5} i

5 x^{2} - 40 x = - 60

x^{2} - 3 x - 10 = 0

x^{2} + 1.2 x + 1

4 x^{2} - 12 x + 9 = 2 x^{2} + 4 x + 2

9 x^{2} - 12 x = - 4

What are the solutions to the equation 80x^2=-16 ?
The solutions to the equation 80x^2=-16 are x= 1/(sqrt(5))i,x=-1/(sqrt(5))i
Find the zeros of 80x^2=-16
The zeros of 80x^2=-16 are x= 1/(sqrt(5))i,x=-1/(sqrt(5))i