What are the solutions to the equation roots x^2+1.2x+1 ?

The solutions to the equation roots x^2+1.2x+1 are x=-3/5+i 4/5 ,x=-3/5-i 4/5

Find the zeros of roots x^2+1.2x+1

The zeros of roots x^2+1.2x+1 are x=-3/5+i 4/5 ,x=-3/5-i 4/5

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roots

x^{2} + 1.2 x + 1

x = - \frac{3}{5} + i \frac{4}{5}, x = - \frac{3}{5} - i \frac{4}{5}

Solution steps

x^{2} + 1.2 x + 1

The roots are the intercepts with the x-axis

(y = 0)

x^{2} + 1.2 x + 1 = 0

Multiply both sides by

10

10 x^{2} + 12 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 10 \cdot 10}{2 \cdot 10}

Simplify

1 2^{2} - 4 \cdot 10 \cdot 10 : 16 i

x_{1, 2} = \frac{- 12 \pm 16 i}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- 12 + 16 i}{2 \cdot 10}, x_{2} = \frac{- 12 - 16 i}{2 \cdot 10}

x = \frac{- 12 + 16 i}{2 \cdot 10} : - \frac{3}{5} + i \frac{4}{5}

x = \frac{- 12 - 16 i}{2 \cdot 10} : - \frac{3}{5} - i \frac{4}{5}

The solutions to the quadratic equation are:

x = - \frac{3}{5} + i \frac{4}{5}, x = - \frac{3}{5} - i \frac{4}{5}

4 x^{2} - 12 x + 9 = 2 x^{2} + 4 x + 2

9 x^{2} - 12 x = - 4

x, x^{2} + y^{2} + z^{2} = 25

- 3 x^{2} + x + 4 = 0

12 - 2 x^{2} = - 20

What are the solutions to the equation roots x^2+1.2x+1 ?
The solutions to the equation roots x^2+1.2x+1 are x=-3/5+i 4/5 ,x=-3/5-i 4/5
Find the zeros of roots x^2+1.2x+1
The zeros of roots x^2+1.2x+1 are x=-3/5+i 4/5 ,x=-3/5-i 4/5