What are the solutions to the equation 2(x^2-7)+3=-3 ?

The solutions to the equation 2(x^2-7)+3=-3 are x=2,x=-2

Find the zeros of 2(x^2-7)+3=-3

The zeros of 2(x^2-7)+3=-3 are x=2,x=-2

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2 (x^{2} - 7) + 3 = - 3

x = 2, x = - 2

Solution steps

2 (x^{2} - 7) + 3 = - 3

Move

3

to the right side

2 (x^{2} - 7) = - 6

Divide both sides by

2

x^{2} - 7 = - 3

Move

7

to the right side

x^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 4, x = - 4

4 = 2

- 4 = - 2

x = 2, x = - 2

x^{2} + 52 = - 12 x

5 (x^{2} - 4) - 5 = - 5

y, x^{2} y^{2} = 1

x^{2} + 2 x + a

x, x^{2} + y^{2} + z^{2} = 9

What are the solutions to the equation 2(x^2-7)+3=-3 ?
The solutions to the equation 2(x^2-7)+3=-3 are x=2,x=-2
Find the zeros of 2(x^2-7)+3=-3
The zeros of 2(x^2-7)+3=-3 are x=2,x=-2