What are the solutions to the equation roots x^2+4x+c ?

The solutions to the equation roots x^2+4x+c are x=-2+sqrt(-c+4),x=-sqrt(-c+4)-2

Find the zeros of roots x^2+4x+c

The zeros of roots x^2+4x+c are x=-2+sqrt(-c+4),x=-sqrt(-c+4)-2

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roots

x^{2} + 4 x + c

x = - 2 + - c + 4, x = - - c + 4 - 2

Solution steps

x^{2} + 4 x + c

The roots are the intercepts with the x-axis

(y = 0)

x^{2} + 4 x + c = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot c}{2 \cdot 1}

Simplify

4^{2} - 4 \cdot 1 \cdot c : 2 4 - c

x_{1, 2} = \frac{- 4 \pm 2 4 - c}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 2 4 - c}{2 \cdot 1}, x_{2} = \frac{- 4 - 2 4 - c}{2 \cdot 1}

x = \frac{- 4 + 2 4 - c}{2 \cdot 1} : - 2 + - c + 4

x = \frac{- 4 - 2 4 - c}{2 \cdot 1} : - - c + 4 - 2

The solutions to the quadratic equation are:

x = - 2 + - c + 4, x = - - c + 4 - 2

9 x^{2} - 25 = 0

x^{2} - 8 x + 8 = - 4

\frac{1}{4} x^{2} + 2 = 0

y^{2} - 15 = 8 y

\frac{2 t ^{2}}{3} = \frac{8}{3} π^{2}

What are the solutions to the equation roots x^2+4x+c ?
The solutions to the equation roots x^2+4x+c are x=-2+sqrt(-c+4),x=-sqrt(-c+4)-2
Find the zeros of roots x^2+4x+c
The zeros of roots x^2+4x+c are x=-2+sqrt(-c+4),x=-sqrt(-c+4)-2