What are the solutions to the equation y^2-15=8y ?

The solutions to the equation y^2-15=8y are y=4+sqrt(31),y=4-sqrt(31)

Find the zeros of y^2-15=8y

The zeros of y^2-15=8y are y=4+sqrt(31),y=4-sqrt(31)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{2} - 15 = 8 y

y = 4 + 31, y = 4 - 31

Decimal Notation

y = 9.56776 \dots, y = - 1.56776 \dots

Solution steps

y^{2} - 15 = 8 y

Move

8 y

to the left side

y^{2} - 15 - 8 y = 0

Write in the standard form

a x^{2} + b x + c = 0

y^{2} - 8 y - 15 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot ( - 15 )}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot (- 15) = 231

y_{1, 2} = \frac{- ( - 8 ) \pm 2 31}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 8 ) + 2 31}{2 \cdot 1}, y_{2} = \frac{- ( - 8 ) - 2 31}{2 \cdot 1}

y = \frac{- ( - 8 ) + 2 31}{2 \cdot 1} : 4 + 31

y = \frac{- ( - 8 ) - 2 31}{2 \cdot 1} : 4 - 31

The solutions to the quadratic equation are:

y = 4 + 31, y = 4 - 31

\frac{2 t ^{2}}{3} = \frac{8}{3} π^{2}

\frac{1}{2} a^{2} - a - \frac{5}{2} = 0

y, x^{2} y - x^{2} + 4 y = 0

25 b^{2} + 24 b + 9 = - 6 b

5 x^{2} - 31 x - 28 = 0

What are the solutions to the equation y^2-15=8y ?
The solutions to the equation y^2-15=8y are y=4+sqrt(31),y=4-sqrt(31)
Find the zeros of y^2-15=8y
The zeros of y^2-15=8y are y=4+sqrt(31),y=4-sqrt(31)