What are the solutions to the equation roots x^2-6x+9 ?

The solutions to the equation roots x^2-6x+9 are x=3

Find the zeros of roots x^2-6x+9

The zeros of roots x^2-6x+9 are x=3

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roots

x^{2} - 6 x + 9

x = 3

Solution steps

x^{2} - 6 x + 9

The roots are the intercepts with the x-axis

(y = 0)

x^{2} - 6 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 9 = 0

x_{1, 2} = \frac{- ( - 6 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 6 )}{2 \cdot 1}

\frac{- ( - 6 )}{2 \cdot 1} = 3

x = 3

The solution to the quadratic equation is:

x = 3

25 x^{2} + 40 x - 9 = 0

10 - 2 x^{2} = - 198

y, y = x y + x^{2} + 1

y, x^{2} + x y + y^{2} = 9

- 7 x = 3 - 4 x^{2}

What are the solutions to the equation roots x^2-6x+9 ?
The solutions to the equation roots x^2-6x+9 are x=3
Find the zeros of roots x^2-6x+9
The zeros of roots x^2-6x+9 are x=3