What are the solutions to the equation z^2+0.35z-1.125=0 ?

The solutions to the equation z^2+0.35z-1.125=0 are z= 9/10 ,z=-5/4

Find the zeros of z^2+0.35z-1.125=0

The zeros of z^2+0.35z-1.125=0 are z= 9/10 ,z=-5/4

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z^{2} + 0.35 z - 1.125 = 0

z = \frac{9}{10}, z = - \frac{5}{4}

Decimal Notation

z = 0.9, z = - 1.25

Solution steps

z^{2} + 0.35 z - 1.125 = 0

Multiply both sides by

1000

1000 z^{2} + 350 z - 1125 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 350 \pm 35 0 ^{2} - 4 \cdot 1000 ( - 1125 )}{2 \cdot 1000}

35 0^{2} - 4 \cdot 1000 (- 1125) = 2150

z_{1, 2} = \frac{- 350 \pm 2150}{2 \cdot 1000}

Separate the solutions

z_{1} = \frac{- 350 + 2150}{2 \cdot 1000}, z_{2} = \frac{- 350 - 2150}{2 \cdot 1000}

z = \frac{- 350 + 2150}{2 \cdot 1000} : \frac{9}{10}

z = \frac{- 350 - 2150}{2 \cdot 1000} : - \frac{5}{4}

The solutions to the quadratic equation are:

z = \frac{9}{10}, z = - \frac{5}{4}

x^{2} - 7 x - 1 = - 1

x^{2} + 6 x + 8

(x + 4) (2 x - a) = 0

6 y^{2} - 3 y - 4 = y^{2}

y^{2} - 17 y + 16 = 0

What are the solutions to the equation z^2+0.35z-1.125=0 ?
The solutions to the equation z^2+0.35z-1.125=0 are z= 9/10 ,z=-5/4
Find the zeros of z^2+0.35z-1.125=0
The zeros of z^2+0.35z-1.125=0 are z= 9/10 ,z=-5/4