What are the solutions to the equation roots x^2+6x+8 ?

The solutions to the equation roots x^2+6x+8 are x=-2,x=-4

Find the zeros of roots x^2+6x+8

The zeros of roots x^2+6x+8 are x=-2,x=-4

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roots

x^{2} + 6 x + 8

x = - 2, x = - 4

Solution steps

x^{2} + 6 x + 8

The roots are the intercepts with the x-axis

(y = 0)

x^{2} + 6 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 8 = 2

x_{1, 2} = \frac{- 6 \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 2}{2 \cdot 1}, x_{2} = \frac{- 6 - 2}{2 \cdot 1}

x = \frac{- 6 + 2}{2 \cdot 1} : - 2

x = \frac{- 6 - 2}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = - 2, x = - 4

(x + 4) (2 x - a) = 0

6 y^{2} - 3 y - 4 = y^{2}

y^{2} - 17 y + 16 = 0

6 x^{2} - 5 x - 4 = 0

(2 x - 1) (x) = 120

What are the solutions to the equation roots x^2+6x+8 ?
The solutions to the equation roots x^2+6x+8 are x=-2,x=-4
Find the zeros of roots x^2+6x+8
The zeros of roots x^2+6x+8 are x=-2,x=-4