What are the solutions to the equation (x+4)(2x-a)=0 ?

The solutions to the equation (x+4)(2x-a)=0 are x=-4,x= a/2

Find the zeros of (x+4)(2x-a)=0

The zeros of (x+4)(2x-a)=0 are x=-4,x= a/2

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(x + 4) (2 x - a) = 0

x = - 4, x = \frac{a}{2}

Solution steps

(x + 4) (2 x - a) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 4 = 0 or 2 x - a = 0

Solve

x + 4 = 0 : x = - 4

Solve

2 x - a = 0 : x = \frac{a}{2}

The solutions to the quadratic equation are:

x = - 4, x = \frac{a}{2}

6 y^{2} - 3 y - 4 = y^{2}

y^{2} - 17 y + 16 = 0

6 x^{2} - 5 x - 4 = 0

(2 x - 1) (x) = 120

x^{2} + 3 x + 13 = 3 - 4 x

What are the solutions to the equation (x+4)(2x-a)=0 ?
The solutions to the equation (x+4)(2x-a)=0 are x=-4,x= a/2
Find the zeros of (x+4)(2x-a)=0
The zeros of (x+4)(2x-a)=0 are x=-4,x= a/2