What are the solutions to the equation factor x^2+3x+13=3-4x ?

The solutions to the equation factor x^2+3x+13=3-4x are x=-2,x=-5

Find the zeros of factor x^2+3x+13=3-4x

The zeros of factor x^2+3x+13=3-4x are x=-2,x=-5

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x^{2} + 3 x + 13 = 3 - 4 x

x = - 2, x = - 5

Solution steps

x^{2} + 3 x + 13 = 3 - 4 x

Move

4 x

to the left side

x^{2} + 7 x + 13 = 3

Move

3

to the left side

x^{2} + 7 x + 10 = 0

Factor

x^{2} + 7 x + 10 : (x + 2) (x + 5)

(x + 2) (x + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or x + 5 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x + 5 = 0 : x = - 5

The solutions to the quadratic equation are:

x = - 2, x = - 5

10 b^{2} + 21 b + 6 = 2 b

x^{2} - 5 x + 2 = - 3 x + 10

(3 x - 7) (5 x - 12) = 0

16 x^{2} = 81

- (n + 2) = 15 (n + 7) n

What are the solutions to the equation factor x^2+3x+13=3-4x ?
The solutions to the equation factor x^2+3x+13=3-4x are x=-2,x=-5
Find the zeros of factor x^2+3x+13=3-4x
The zeros of factor x^2+3x+13=3-4x are x=-2,x=-5