What are the solutions to the equation 2k^2-16k+168=0 ?

The solutions to the equation 2k^2-16k+168=0 are k=4+2sqrt(17)i,k=4-2sqrt(17)i

Find the zeros of 2k^2-16k+168=0

The zeros of 2k^2-16k+168=0 are k=4+2sqrt(17)i,k=4-2sqrt(17)i

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2 k^{2} - 16 k + 168 = 0

k = 4 + 217 i, k = 4 - 217 i

Solution steps

2 k^{2} - 16 k + 168 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 2 \cdot 168}{2 \cdot 2}

Simplify

(- 16)^{2} - 4 \cdot 2 \cdot 168 : 817 i

k_{1, 2} = \frac{- ( - 16 ) \pm 8 17 i}{2 \cdot 2}

Separate the solutions

k_{1} = \frac{- ( - 16 ) + 8 17 i}{2 \cdot 2}, k_{2} = \frac{- ( - 16 ) - 8 17 i}{2 \cdot 2}

k = \frac{- ( - 16 ) + 8 17 i}{2 \cdot 2} : 4 + 217 i

k = \frac{- ( - 16 ) - 8 17 i}{2 \cdot 2} : 4 - 217 i

The solutions to the quadratic equation are:

k = 4 + 217 i, k = 4 - 217 i

2 x (4 - 7 x) = - 9

x^{2} + 8 x + 17

0 = 30 + 3 t - \frac{9.8 t ^{2}}{2}

r^{2} - r + 49 = 0

x^{2} - 101 = - 1

What are the solutions to the equation 2k^2-16k+168=0 ?
The solutions to the equation 2k^2-16k+168=0 are k=4+2sqrt(17)i,k=4-2sqrt(17)i
Find the zeros of 2k^2-16k+168=0
The zeros of 2k^2-16k+168=0 are k=4+2sqrt(17)i,k=4-2sqrt(17)i