What are the solutions to the equation -3(x+2)^2=24 ?

The solutions to the equation -3(x+2)^2=24 are x=2sqrt(2)i-2,x=-2sqrt(2)i-2

Find the zeros of -3(x+2)^2=24

The zeros of -3(x+2)^2=24 are x=2sqrt(2)i-2,x=-2sqrt(2)i-2

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- 3 (x + 2)^{2} = 24

x = 22 i - 2, x = - 22 i - 2

Solution steps

- 3 (x + 2)^{2} = 24

Divide both sides by

- 3

(x + 2)^{2} = - 8

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 2 = - 8 : x = 22 i - 2

Solve

x + 2 = - - 8 : x = - 22 i - 2

The solutions to the quadratic equation are:

x = 22 i - 2, x = - 22 i - 2

150 x^{2} + x = 0

x^{2} + 2 x + 17 = 0

4 x^{2} + 20 x = - 17

x^{2} - b x + 16

y, y^{2} = - x^{2}

What are the solutions to the equation -3(x+2)^2=24 ?
The solutions to the equation -3(x+2)^2=24 are x=2sqrt(2)i-2,x=-2sqrt(2)i-2
Find the zeros of -3(x+2)^2=24
The zeros of -3(x+2)^2=24 are x=2sqrt(2)i-2,x=-2sqrt(2)i-2