What are the solutions to the equation 2x^2+82=-24x ?

The solutions to the equation 2x^2+82=-24x are x=-6+sqrt(5)i,x=-6-sqrt(5)i

Find the zeros of 2x^2+82=-24x

The zeros of 2x^2+82=-24x are x=-6+sqrt(5)i,x=-6-sqrt(5)i

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2 x^{2} + 82 = - 24 x

x = - 6 + 5 i, x = - 6 - 5 i

Solution steps

2 x^{2} + 82 = - 24 x

Move

24 x

to the left side

2 x^{2} + 82 + 24 x = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} + 24 x + 82 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 2 \cdot 82}{2 \cdot 2}

Simplify

2 4^{2} - 4 \cdot 2 \cdot 82 : 45 i

x_{1, 2} = \frac{- 24 \pm 4 5 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 24 + 4 5 i}{2 \cdot 2}, x_{2} = \frac{- 24 - 4 5 i}{2 \cdot 2}

x = \frac{- 24 + 4 5 i}{2 \cdot 2} : - 6 + 5 i

x = \frac{- 24 - 4 5 i}{2 \cdot 2} : - 6 - 5 i

The solutions to the quadratic equation are:

x = - 6 + 5 i, x = - 6 - 5 i

- x^{2} - 9 x + 3 = 0

- 4 n^{2} - 1 = - 4 n

2 x (6 - 5 x) = - 7

- 3 r^{2} - r - 10 = - 4 r^{2}

x^{2} + 10 x + 25 = 0

What are the solutions to the equation 2x^2+82=-24x ?
The solutions to the equation 2x^2+82=-24x are x=-6+sqrt(5)i,x=-6-sqrt(5)i
Find the zeros of 2x^2+82=-24x
The zeros of 2x^2+82=-24x are x=-6+sqrt(5)i,x=-6-sqrt(5)i