What is the answer to solvefor y,x^2+4xy=16 ?

The answer to solvefor y,x^2+4xy=16 is y=(16-x^2)/(4x);\quad x\ne 0

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solvefor y,x^2+4xy=16

solve for

y, x^{2} + 4 x y = 16

y = \frac{16 - x ^{2}}{4 x}; x \neq = 0

Solution steps

x^{2} + 4 x y = 16

Move

x^{2}

to the right side

4 x y = 16 - x^{2}

Divide both sides by

4 x; x \neq = 0

y = \frac{16 - x ^{2}}{4 x}; x \neq = 0

9 x^{2} + 3 = 0

w, V = (2 w - 5)^{2}

a^{2} + 6 a - 26 = 0

3 p^{2} - 4 = - 24

x^{2} - 8 x - 56 = 0

What is the answer to solvefor y,x^2+4xy=16 ?
The answer to solvefor y,x^2+4xy=16 is y=(16-x^2)/(4x);\quad x\ne 0