What are the solutions to the equation 2(x-16)^2=-8 ?

The solutions to the equation 2(x-16)^2=-8 are x=2i+16,x=-2i+16

Find the zeros of 2(x-16)^2=-8

The zeros of 2(x-16)^2=-8 are x=2i+16,x=-2i+16

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 (x - 16)^{2} = - 8

x = 2 i + 16, x = - 2 i + 16

Solution steps

2 (x - 16)^{2} = - 8

Divide both sides by

2

(x - 16)^{2} = - 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 16 = - 4 : x = 2 i + 16

Solve

x - 16 = - - 4 : x = - 2 i + 16

The solutions to the quadratic equation are:

x = 2 i + 16, x = - 2 i + 16

(5 x + 2) (- x - 4) = 0

3 x^{2} + 42 x = - 171

4 x^{2} + 36 x = - 77

x, 0 = 3 m^{2} x^{2} + 2 m x - 5

4 (x + 7)^{2} = 16

What are the solutions to the equation 2(x-16)^2=-8 ?
The solutions to the equation 2(x-16)^2=-8 are x=2i+16,x=-2i+16
Find the zeros of 2(x-16)^2=-8
The zeros of 2(x-16)^2=-8 are x=2i+16,x=-2i+16