What are the solutions to the equation 2(x-2)^2-39=-31 ?

The solutions to the equation 2(x-2)^2-39=-31 are x=4,x=0

Find the zeros of 2(x-2)^2-39=-31

The zeros of 2(x-2)^2-39=-31 are x=4,x=0

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2 (x - 2)^{2} - 39 = - 31

x = 4, x = 0

Solution steps

2 (x - 2)^{2} - 39 = - 31

Move

39

to the right side

2 (x - 2)^{2} = 8

Divide both sides by

2

(x - 2)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 2 = 4 : x = 4

Solve

x - 2 = - 4 : x = 0

The solutions to the quadratic equation are:

x = 4, x = 0

x^{2} + 8 x - 24 = 3 x

x, x^{2} + y^{2} + z^{2} = 0

x^{2} + 2 x = - 2 x

3 x^{2} - 14 x + 4 = 0

x, (x - h)^{2} + (y - k)^{2} = r^{2}

What are the solutions to the equation 2(x-2)^2-39=-31 ?
The solutions to the equation 2(x-2)^2-39=-31 are x=4,x=0
Find the zeros of 2(x-2)^2-39=-31
The zeros of 2(x-2)^2-39=-31 are x=4,x=0