What are the solutions to the equation 4x^2+17x+18=x^2 ?

The solutions to the equation 4x^2+17x+18=x^2 are x=(-17+sqrt(73))/6 ,x=(-17-sqrt(73))/6

Find the zeros of 4x^2+17x+18=x^2

The zeros of 4x^2+17x+18=x^2 are x=(-17+sqrt(73))/6 ,x=(-17-sqrt(73))/6

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4 x^{2} + 17 x + 18 = x^{2}

x = \frac{- 17 + 73}{6}, x = \frac{- 17 - 73}{6}

Decimal Notation

x = - 1.40933 \dots, x = - 4.25733 \dots

Solution steps

4 x^{2} + 17 x + 18 = x^{2}

Move

x^{2}

to the left side

3 x^{2} + 17 x + 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 3 \cdot 18}{2 \cdot 3}

1 7^{2} - 4 \cdot 3 \cdot 18 = 73

x_{1, 2} = \frac{- 17 \pm 73}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 17 + 73}{2 \cdot 3}, x_{2} = \frac{- 17 - 73}{2 \cdot 3}

x = \frac{- 17 + 73}{2 \cdot 3} : \frac{- 17 + 73}{6}

x = \frac{- 17 - 73}{2 \cdot 3} : \frac{- 17 - 73}{6}

The solutions to the quadratic equation are:

x = \frac{- 17 + 73}{6}, x = \frac{- 17 - 73}{6}

- x^{2} + 8 = 2 x

x^{2} + 4 x + 1

x^{2} + 2 x - 2

6 w^{2} - 7 w - 3 = 0

2 w^{2} - 12 w + 18 = 0

What are the solutions to the equation 4x^2+17x+18=x^2 ?
The solutions to the equation 4x^2+17x+18=x^2 are x=(-17+sqrt(73))/6 ,x=(-17-sqrt(73))/6
Find the zeros of 4x^2+17x+18=x^2
The zeros of 4x^2+17x+18=x^2 are x=(-17+sqrt(73))/6 ,x=(-17-sqrt(73))/6