What are the solutions to the equation k^2-6=0 ?

The solutions to the equation k^2-6=0 are k=sqrt(6),k=-sqrt(6)

Find the zeros of k^2-6=0

The zeros of k^2-6=0 are k=sqrt(6),k=-sqrt(6)

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k^{2} - 6 = 0

k = 6, k = - 6

Decimal Notation

k = 2.44948 \dots, k = - 2.44948 \dots

Solution steps

k^{2} - 6 = 0

Move

6

to the right side

k^{2} = 6

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

k = 6, k = - 6

2 r^{2} + 13 r + 17 = 0

180 = (x + 20) x 128

y, x^{2} - 4 y^{2} = 0

y, x^{2} + 5 x + y^{2} - y + 7 = 0

x, y = 2 - 2 x^{2}

What are the solutions to the equation k^2-6=0 ?
The solutions to the equation k^2-6=0 are k=sqrt(6),k=-sqrt(6)
Find the zeros of k^2-6=0
The zeros of k^2-6=0 are k=sqrt(6),k=-sqrt(6)