What are the solutions to the equation solvefor y,x^2-4y^2=0 ?

The solutions to the equation solvefor y,x^2-4y^2=0 are y= x/2 ,y=-x/2

Find the zeros of solvefor y,x^2-4y^2=0

The zeros of solvefor y,x^2-4y^2=0 are y= x/2 ,y=-x/2

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solve for

y, x^{2} - 4 y^{2} = 0

y = \frac{x}{2}, y = - \frac{x}{2}

Solution steps

x^{2} - 4 y^{2} = 0

Move

x^{2}

to the right side

- 4 y^{2} = - x^{2}

Divide both sides by

- 4

y^{2} = \frac{x ^{2}}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = \frac{x ^{2}}{4}, y = - \frac{x ^{2}}{4}

Simplify

\frac{x ^{2}}{4} : \frac{x}{2}

Simplify

- \frac{x ^{2}}{4} : - \frac{x}{2}

y = \frac{x}{2}, y = - \frac{x}{2}

y, x^{2} + 5 x + y^{2} - y + 7 = 0

x, y = 2 - 2 x^{2}

2 x^{2} - 8 = 120

x^{2} - a

12 x^{2} - 216 x + 504 = 0

What are the solutions to the equation solvefor y,x^2-4y^2=0 ?
The solutions to the equation solvefor y,x^2-4y^2=0 are y= x/2 ,y=-x/2
Find the zeros of solvefor y,x^2-4y^2=0
The zeros of solvefor y,x^2-4y^2=0 are y= x/2 ,y=-x/2