What are the solutions to the equation 2r^2+13r+17=0 ?

The solutions to the equation 2r^2+13r+17=0 are r=(-13+sqrt(33))/4 ,r=(-13-sqrt(33))/4

Find the zeros of 2r^2+13r+17=0

The zeros of 2r^2+13r+17=0 are r=(-13+sqrt(33))/4 ,r=(-13-sqrt(33))/4

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2 r^{2} + 13 r + 17 = 0

r = \frac{- 13 + 33}{4}, r = \frac{- 13 - 33}{4}

Decimal Notation

r = - 1.81385 \dots, r = - 4.68614 \dots

Solution steps

2 r^{2} + 13 r + 17 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 2 \cdot 17}{2 \cdot 2}

1 3^{2} - 4 \cdot 2 \cdot 17 = 33

r_{1, 2} = \frac{- 13 \pm 33}{2 \cdot 2}

Separate the solutions

r_{1} = \frac{- 13 + 33}{2 \cdot 2}, r_{2} = \frac{- 13 - 33}{2 \cdot 2}

r = \frac{- 13 + 33}{2 \cdot 2} : \frac{- 13 + 33}{4}

r = \frac{- 13 - 33}{2 \cdot 2} : \frac{- 13 - 33}{4}

The solutions to the quadratic equation are:

r = \frac{- 13 + 33}{4}, r = \frac{- 13 - 33}{4}

180 = (x + 20) x 128

y, x^{2} - 4 y^{2} = 0

y, x^{2} + 5 x + y^{2} - y + 7 = 0

x, y = 2 - 2 x^{2}

2 x^{2} - 8 = 120

What are the solutions to the equation 2r^2+13r+17=0 ?
The solutions to the equation 2r^2+13r+17=0 are r=(-13+sqrt(33))/4 ,r=(-13-sqrt(33))/4
Find the zeros of 2r^2+13r+17=0
The zeros of 2r^2+13r+17=0 are r=(-13+sqrt(33))/4 ,r=(-13-sqrt(33))/4