What are the solutions to the equation 16a^2+8a-8=-5 ?

The solutions to the equation 16a^2+8a-8=-5 are a= 1/4 ,a=-3/4

Find the zeros of 16a^2+8a-8=-5

The zeros of 16a^2+8a-8=-5 are a= 1/4 ,a=-3/4

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16 a^{2} + 8 a - 8 = - 5

a = \frac{1}{4}, a = - \frac{3}{4}

Decimal Notation

a = 0.25, a = - 0.75

Solution steps

16 a^{2} + 8 a - 8 = - 5

Move

5

to the left side

16 a^{2} + 8 a - 3 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 16 ( - 3 )}{2 \cdot 16}

8^{2} - 4 \cdot 16 (- 3) = 16

a_{1, 2} = \frac{- 8 \pm 16}{2 \cdot 16}

Separate the solutions

a_{1} = \frac{- 8 + 16}{2 \cdot 16}, a_{2} = \frac{- 8 - 16}{2 \cdot 16}

a = \frac{- 8 + 16}{2 \cdot 16} : \frac{1}{4}

a = \frac{- 8 - 16}{2 \cdot 16} : - \frac{3}{4}

The solutions to the quadratic equation are:

a = \frac{1}{4}, a = - \frac{3}{4}

x^{2} + 7 x - 10 = - 2 x

x^{2} + x - 22 = x + 3

- (x - 2)^{2} + 4

4 x^{2} + 37 = - 20 x

x^{2} - 61 x + 900 = 0

What are the solutions to the equation 16a^2+8a-8=-5 ?
The solutions to the equation 16a^2+8a-8=-5 are a= 1/4 ,a=-3/4
Find the zeros of 16a^2+8a-8=-5
The zeros of 16a^2+8a-8=-5 are a= 1/4 ,a=-3/4