What are the solutions to the equation 4a^2+4a+1=0 ?

The solutions to the equation 4a^2+4a+1=0 are a=-1/2

Find the zeros of 4a^2+4a+1=0

The zeros of 4a^2+4a+1=0 are a=-1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 a^{2} + 4 a + 1 = 0

a = - \frac{1}{2}

Decimal Notation

a = - 0.5

Solution steps

4 a^{2} + 4 a + 1 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

4^{2} - 4 \cdot 4 \cdot 1 = 0

a_{1, 2} = \frac{- 4 \pm 0}{2 \cdot 4}

a = \frac{- 4}{2 \cdot 4}

\frac{- 4}{2 \cdot 4} = - \frac{1}{2}

a = - \frac{1}{2}

The solution to the quadratic equation is:

a = - \frac{1}{2}

y, x^{2} - x y + 2 y - 2 = 0

6 x^{2} - 8 x + 6 = 0

y, y^{2} - x^{2} = 0

6 x = 2 x^{2} - 7 x + 14

x, x y^{4} + x^{2} y = x + 3 y

What are the solutions to the equation 4a^2+4a+1=0 ?
The solutions to the equation 4a^2+4a+1=0 are a=-1/2
Find the zeros of 4a^2+4a+1=0
The zeros of 4a^2+4a+1=0 are a=-1/2