What is the answer to solvefor y,x^2y=y-7 ?

The answer to solvefor y,x^2y=y-7 is y=-7/(x^2-1);\quad x\ne 1,x\ne-1

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solvefor y,x^2y=y-7

solve for

y, x^{2} y = y - 7

y = - \frac{7}{x ^{2} - 1}; x \neq = 1, x \neq = - 1

Solution steps

x^{2} y = y - 7

Move

y

to the left side

x^{2} y - y = - 7

Factor

x^{2} y - y : y (x^{2} - 1)

y (x^{2} - 1) = - 7

Divide both sides by

x^{2} - 1; x \neq = 1, x \neq = - 1

y = - \frac{7}{x ^{2} - 1}; x \neq = 1, x \neq = - 1

2 x^{2} - 7 x + 4

r^{2} - 6 r + 12 = 0

(1 - k) x^{2} + x + k = 0

81 = \frac{n}{2} (1.5 + n)

2 x^{2} - 19 x - 10 = 0

What is the answer to solvefor y,x^2y=y-7 ?
The answer to solvefor y,x^2y=y-7 is y=-7/(x^2-1);\quad x\ne 1,x\ne-1