What are the solutions to the equation 0=x^2+20x-60 ?

The solutions to the equation 0=x^2+20x-60 are x=2(2sqrt(10)-5),x=-2(5+2sqrt(10))

Find the zeros of 0=x^2+20x-60

The zeros of 0=x^2+20x-60 are x=2(2sqrt(10)-5),x=-2(5+2sqrt(10))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0 = x^{2} + 20 x - 60

x = 2 (210 - 5), x = - 2 (5 + 210)

Decimal Notation

x = 2.64911 \dots, x = - 22.64911 \dots

Solution steps

0 = x^{2} + 20 x - 60

Switch sides

x^{2} + 20 x - 60 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 1 \cdot ( - 60 )}{2 \cdot 1}

2 0^{2} - 4 \cdot 1 \cdot (- 60) = 810

x_{1, 2} = \frac{- 20 \pm 8 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 20 + 8 10}{2 \cdot 1}, x_{2} = \frac{- 20 - 8 10}{2 \cdot 1}

x = \frac{- 20 + 8 10}{2 \cdot 1} : 2 (210 - 5)

x = \frac{- 20 - 8 10}{2 \cdot 1} : - 2 (5 + 210)

The solutions to the quadratic equation are:

x = 2 (210 - 5), x = - 2 (5 + 210)

b x^{2} - b = x - b^{2} x

3 (x^{2} - 7) - 4 = - 7

x^{2} - 31 = 2 x

2 x^{2} + 6 x - 7 = 2

x, 3 x^{2} + 30 x - 5 = 0

What are the solutions to the equation 0=x^2+20x-60 ?
The solutions to the equation 0=x^2+20x-60 are x=2(2sqrt(10)-5),x=-2(5+2sqrt(10))
Find the zeros of 0=x^2+20x-60
The zeros of 0=x^2+20x-60 are x=2(2sqrt(10)-5),x=-2(5+2sqrt(10))